In projectile motion, the modulus of rate of change of velocity
In projectile motion, the modulus of rate of change of velocity
- A
is constant
- B
first increases then decreases
- C
first decreases then increases
- D
None of the above
Similar Questions
At what angle the particle should be projected to cover maximum range ?
At what angle the particle should be projected to cover maximum range ?
Range of a bullet fired at $45^o$ to horizontal is $980m$. If the bullet is fired at same angle from a car travelling horizontally at $18\, km/hr$ towards target then range will be increased by :-
Range of a bullet fired at $45^o$ to horizontal is $980m$. If the bullet is fired at same angle from a car travelling horizontally at $18\, km/hr$ towards target then range will be increased by :-
At what angle of elevation, should a projectile be projected with velocity $20 \,ms ^{-1}$, so as to reach a maximum height of $10 \,m$ ?
At what angle of elevation, should a projectile be projected with velocity $20 \,ms ^{-1}$, so as to reach a maximum height of $10 \,m$ ?
The position of a projectile launched from the origin at $t = 0$ is given by $\vec r = \left( {40\hat i + 50\hat j} \right)\,m$ at $t = 2\,s$. If the projectile was launched at an angle $\theta$ from the horizontal, then $\theta$ is (take $g = 10\, ms^{-2}$)
The position of a projectile launched from the origin at $t = 0$ is given by $\vec r = \left( {40\hat i + 50\hat j} \right)\,m$ at $t = 2\,s$. If the projectile was launched at an angle $\theta$ from the horizontal, then $\theta$ is (take $g = 10\, ms^{-2}$)
- [JEE MAIN 2014]
A projectile cover double range as compare to its maximum height attained. The angle of projection is
A projectile cover double range as compare to its maximum height attained. The angle of projection is